2(x^2-10x+49)=16

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Solution for 2(x^2-10x+49)=16 equation:



2(x^2-10x+49)=16
We move all terms to the left:
2(x^2-10x+49)-(16)=0
We multiply parentheses
2x^2-20x+98-16=0
We add all the numbers together, and all the variables
2x^2-20x+82=0
a = 2; b = -20; c = +82;
Δ = b2-4ac
Δ = -202-4·2·82
Δ = -256
Delta is less than zero, so there is no solution for the equation

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